Câu hỏi:
Giúp em bài tập về nhà Hóa học lớp 9 câu hỏi như sau: Bài 3. Hoàn thành chuỗi phản ứng:
a. MnO2 →Cl2 →FeCl3 → Fe(OH)3 → FeCl3 →AgCl →Cl2.
b. KMnO4 → Cl2 →HCl →CuCl2 → BaCl2 → BaSO4.
c. NaCl→ HCl → Cl2 → FeCl3 →NaCl →NaOH →NaCl →Cl2 →CaCl2 →AgCl →Ag.
d. NaCl →HCl →KCl →Cl2 →NaCl →H2 →HCl →Cl2 →CuCl2 →Cu(OH)2 →CuSO4 → K2SO4 →KNO3.
Trả lời 2:
Gia Sư Hoàng Khang gữi câu trả lời dành cho bạn:
a)
MnO2+4HCl->MnCl2+Cl2+2H2O
2Fe+3Cl2->2FeCl3
FeCl3+3NaOH->Fe(OH)3+3NaCl
Fe(OH)3+3HCl->FeCl3+3H2O
FeCl3+3AgNO3->Fe(NO3)3+3AgCl
2AgCl->2Ag+Cl2
b)
2KMnO4+16HCl->2KCl+2MnCl2+5Cl2+8H2O
Cl2+H2->2HCl
CuO+2HCl->CuCl2+H2O
CuCl2+Ba(OH)2->BaCl2+Cu(OH)2
BaCl2+Na2SO4->BaSO4+2NaCl
c)
2NaCl+H2SO4->Na2SO4+2HCl
2HCl->H2+Cl2
2Fe+3Cl2->2FeCl3
FeCl3+3NaOH->Fe(OH)3+3NaCl
2NaCl+2H2O->2NaOH+H2+Cl2
NaOH+HCl->NaCl+H2O
2NaCl->2Na+Cl2
Cl2+Ca->CaCl2
CaCl2+2AgNO3->Ca(NO3)2+2AgCl
2AgCl->2Ag+Cl2
d)
2NaCl+H2SO4->Na2SO4+2HCl
KOH+HCl->KCl+H2O
2KCl+2H2O->2KOH+Cl2+H2
Cl2+2NaOH->NaCl+NaClO+H2O
2NaCl+2H2O->2NaOH+H2+Cl2
H2+Cl2->2HCl
MnO2+4HCl->MnCl2+Cl2+2H2O
Cl2+Cu->CuCl2
CuCl2+2NaOH->Cu(OH)2+2NaCl
Cu(OH)2+H2SO4->CuSO4+2H2O
CuSO4+2KOH->K2SO4+Cu(OH)2
K2SO4+Ba(NO3)2->BaSO4+2KNO3
Trả lời 1:
Gia Sư Hoàng Khang gữi câu trả lời dành cho bạn:
Giải đáp:
a.
$MnO_2 + 4HCl đ \buildrel{{t^o}}\over\longrightarrow MnCl_2 + Cl_2 +2H_2O$
$3Cl_2 + 2Fe \buildrel{{t^o}}\over\longrightarrow 2FeCl_3$
$FeCl3 + 3NaOH → Fe(OH)_3 + 3NaCl$
$Fe(OH)_3 +3HCl → FeCl_3 + 3H_2O$
$FeCl_3 + 3AgNO_3 → 3AgCl +Fe(NO_3)_3$
$2AgCl \buildrel{{t^o}}\over\longrightarrow 2Ag + Cl_2$
b.
$2KMnO4 + 16HCl đ \buildrel{{t^o}}\over\longrightarrow 2KCl + 2MnCl_2 +5Cl_2 +8H_2O$
$Cl_2 + H_2 \buildrel{{t^o}}\over\longrightarrow 2HCl$
$2HCl + CuO → CuCl_2 + H_2O$
$CuCl_2 + Ba(OH)_2 → Cu(OH)_2 + BaCl_2$
$BaCl_2 + H_2SO_4 → BaSO_4 + 2HCl$
c.
$2NaCl + H_2SO_4 đ \buildrel{{t^o}}\over\longrightarrow Na_2SO_4 + 2HCl$
$2HCl \xrightarrow{{dp{\text{dd}}}} H_2 + Cl_2$
$3Cl_2 + 2Fe \buildrel{{t^o}}\over\longrightarrow 2FeCl_3$
$FeCl_3 + 3NaOH → 3NaCl + Fe(OH)_3$
$2NaCl + 2H_2O \xrightarrow[{cmn}]{{dp{\text{dd}}}} 2NaOH +Cl_2 + H_2$
$NaOH + HCl → NaCl + H_2O$
$Cl_2 + Ca \buildrel{{t^o}}\over\longrightarrow CaCl_2$
$CaCl_2 + 2AgNO_3 → 2AgCl + Ca(NO_3)_2$
$2AgCl \buildrel{{t^o}}\over\longrightarrow 2Ag+ Cl_2$
d.
$2NaCl + H_2SO_4đ \buildrel{{t^o}}\over\longrightarrow Na_2SO_4 + 2HCl$
$2HCl +2 K → 2KCl +H_2$
$2KCl \xrightarrow{{dpnc}}2K +Cl_2$
$Cl_2 + 2Na \buildrel{{t^o}}\over\longrightarrow 2NaCl$
$2NaCl + 2H_2O \xrightarrow[{cmn}]{{dp{\text{dd}}}} 2NaOH + Cl_2 + H_2$
$H_2 + Cl_2 \buildrel{{t^o}}\over\longrightarrow 2HCl$
$2HCl \xrightarrow{{dp{\text{dd}}}} H_2 + Cl_2$
$Cl_2 + Cu \buildrel{{t^o}}\over\longrightarrow CuCl_2$
$CuCl_2 + 2NaOH → 2NaCl + Cu(OH)_2$
$Cu(OH)_2 + H_2SO_4 → CuSO_4 + 2H_2O$
$CuSO_4 + 2KOH → K_2SO_4 + Cu(OH)_2$
$K_2SO_4 + Ba(NO_3)_2 → 2KNO_3 + BaSO_4$
